supercuspidal

S1U1P3E1R1C3U1S1P3I1D2A1L1

adjective

That has a zero Jacquet functor for every proper parabolic subgroup

Scrabble 20
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Meanings

adjectivesupercuspidal (not comparable)
  1. not comparablemathematicsThat has a zero Jacquet functor for every proper parabolic subgroup

    A theorem of Bernstein states that for any compact open subgroup K of G(k), there are, up to unramified twists, only finitely many K-spherical supercuspidal representations of G(k).

    2015, Manish Mishra, “A Galois side analogue of a theorem of Bernstein”, in arXiv

Origin

From super- + cuspidal.

Full word history & related roots →
Cite this entry
APA

supercuspidal. (n.d.). In WatkinsX Dictionary. Retrieved November 3, 2026, from https://dictionary.watkinsx.com/word/supercuspidal

MLA

“supercuspidal.” WatkinsX Dictionary, https://dictionary.watkinsx.com/word/supercuspidal. Accessed November 3, 2026.

Chicago

WatkinsX Dictionary, s.v. “supercuspidal,” accessed November 3, 2026, https://dictionary.watkinsx.com/word/supercuspidal.

Source: supercuspidal on Wiktionary, CC BY-SA 4.0.